vdk_binary seems to be done
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@@ -0,0 +1,417 @@
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/**
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* Miscellaneous binary utility functions
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*
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* @module
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*/
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export {
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// basic bytes functions
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bytes_eq,
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bytes_concat,
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strong_rand_bytes,
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bytes_to_bigint,
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bigint_to_bytes,
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// basic bits functions
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bits_null,
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bits_zeros,
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bits_ones,
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bits_i0th,
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bits_concat
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};
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export type {
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bits
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};
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/**
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* Bytewise equality of two `Uint8Array`s
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*/
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function
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bytes_eq
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(arr1 : Uint8Array,
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arr2 : Uint8Array)
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: boolean
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{
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if (arr1.length !== arr2.length)
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return false;
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else
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{
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let len : number = arr1.length;
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for (let i = 0;
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i < len;
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i++)
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{
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if (arr1[i] !== arr2[i])
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return false;
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}
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return true;
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}
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}
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/**
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* Concatenate two arrays
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*/
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function
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bytes_concat
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(arr1 : Uint8Array,
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arr2 : Uint8Array)
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: Uint8Array
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{
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let len1 : number = arr1.length;
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let len2 : number = arr2.length;
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let arr1_idx0_offset : number = 0;
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let arr2_idx0_offset : number = len1;
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let result_len : number = len1 + len2;
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let result : Uint8Array = new Uint8Array(result_len);
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// copy first array into result
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for (let arr1_idx0 = 0;
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arr1_idx0 < len1;
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arr1_idx0++)
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{
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// no offset here
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let result_idx0 : number = arr1_idx0 + arr1_idx0_offset;
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result[result_idx0] = arr1[arr1_idx0];
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}
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// copy second array into result
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for (let arr2_idx0 = 0;
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arr2_idx0 < len2;
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arr2_idx0++)
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{
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// offset by the length of the first array
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let result_idx0 : number = arr2_idx0 + arr2_idx0_offset;
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result[result_idx0] = arr2[arr2_idx0];
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}
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return result;
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}
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/**
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* Cryptographically random bytes
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*/
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function
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strong_rand_bytes
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(how_many : number)
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: Uint8Array
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{
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let arr = new Uint8Array(how_many);
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(new Crypto()).getRandomValues(arr);
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return arr;
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}
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/**
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* Convert a byte array to a bigint
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*
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* Equivalent to `binary:decode_unsigned/1` from Erlang
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*/
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function
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bytes_to_bigint
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(bytes: Uint8Array)
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: bigint
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{
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let n : bigint = 0n;
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for (let b of bytes) {
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// move first, then add
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// otherwise it ends on a move
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// imperative languages are for losers
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n <<= 8n;
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n += BigInt(b);
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}
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return n;
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}
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/**
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* Convert a bigint to a byte array
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*
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* Equivalent to `binary:encode_unsigned/1` from Erlang
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*
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* Requires input to be positive
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*/
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function
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bigint_to_bytes
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(q: bigint)
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: Uint8Array
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{
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if (q < 0n) {
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throw new Error('q < 0n: ' + q);
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}
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let arr_reverse = [];
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while (q > 0n) {
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let r = Number(q % 256n);
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q /= 256n;
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arr_reverse.push(r);
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}
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arr_reverse.reverse();
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return new Uint8Array(arr_reverse);
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}
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/**
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* Oh no, bitstrings in a language that only has bytestrings
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*
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* By convention these are `Uint8Array`s with byte length `ceil(bit_length /
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* 8)`, and all trailing bits are zero.
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*/
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type bits =
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{bit_length : number,
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bytes : Uint8Array};
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/**
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* Get an uninitialized bitstring
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*
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* @internal
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*/
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function
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bits_null
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(bit_length : number)
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: bits
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{
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let byte_length : number = Math.ceil(bit_length / 8);
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let result : Uint8Array = new Uint8Array(byte_length);
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return {bit_length : bit_length,
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bytes : result};
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}
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/**
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* Get a bitstring of a given length where every value is 0.
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*/
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function
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bits_zeros
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(bit_length : number)
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: bits
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{
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let byte_length : number = Math.ceil(bit_length / 8);
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let result : Uint8Array = new Uint8Array(byte_length);
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for (let i0 = 0;
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i0 < byte_length;
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i0++)
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{
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result[i0] = 0;
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}
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return {bit_length : bit_length,
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bytes : result};
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}
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/**
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* Get a bitstring of a given length where every value is 1.
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*/
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function
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bits_ones
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(bit_length : number)
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: bits
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{
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let byte_length : number = Math.ceil(bit_length / 8);
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let result : Uint8Array = new Uint8Array(byte_length);
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// fill everything except the last byte with 255s
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for (let i0 = 0;
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i0 < (byte_length - 1);
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i0++)
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{
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result[i0] = 255;
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}
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// alright so the last byte
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// ok so the number of leading 0s is
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// 8 - (bit_length % 8)
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let num_trailing_zero_bits : number = 8 - (bit_length % 8);
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// the trailing byte is 255 << that
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// e.g. 3 trailing 0s
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// 1111_1111 -> 1111_1000
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let last_byte : number = 255 << num_trailing_zero_bits;
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let last_byte_idx0 : number = byte_length - 1;
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result[last_byte_idx0] = last_byte;
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return {bit_length : bit_length,
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bytes : result};
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}
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/**
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* Get the bit at a given 0-index
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*/
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function
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bits_i0th
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(bit_idx0 : number,
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bits : bits)
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: number
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{
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// first task is figuring out what byte we're at
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// for instance if we want bit 27
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// 3*8 = 24 =< 27 < 4*8
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// so it's Math.floor(bit_idx0 / 8)
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let byte_idx0 : number = Math.floor(bit_idx0 / 8);
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// let's fetch the byte and work with that
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let the_byte : number = bits.bytes[byte_idx0];
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// ok so let's go with 27 again
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// 27 = 3 mod 8
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// so we bitshift right by (8 - 3)
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// and then take the remainder dividing by 2
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// --B-_---- -> ----_---B -> 0000_000B
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let bsr : number = 8 - (bit_idx0 % 8);
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return (the_byte >> bsr) % 2;
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}
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/**
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* Concatenate two bitstrings
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*/
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function
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bits_concat
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(bits1 : bits,
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bits2 : bits)
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: bits
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{
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let result_bit_length : number = bits1.bit_length + bits2.bit_length;
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let bytes1 : Uint8Array = bits1.bytes;
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let bytes2 : Uint8Array = bits2.bytes;
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// using zeros here because of our xor trick in a minute
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let result_bits : bits = bits_null(result_bit_length);
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let result_bytes : Uint8Array = result_bits.bytes;
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// go along each byte in result, and compute the byte boundary
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for (let i = 0;
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i < result_bytes.length;
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i++)
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{
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// ABCD_EFGH _
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// 0123_4567 8
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// this is the bit index of the leftmost bit in this byte
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let start_bit_bi0 : number = i * 8;
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let next_start_bit_bi0 : number = start_bit_bi0 + 8;
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// does the bit at the beginning of this byte correspond to the first array?
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// strict comparison:
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// suppose i = 0,
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// suppose bit_length1 is 0
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// then this says no, go to second array
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// suppose bl1 = 1,
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// this says start at first array
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let start_bit_is_of_first_array : boolean = start_bit_bi0 < bits1.bit_length;
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// weak comparison:
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// suppose bit_length1 = 8
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// ABCD_EFGH _
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// 0123_4567 8
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// ^
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// start_bit_bi0 ^ next_start_bit_bi0
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let stop_bit_is_of_first_array : boolean = next_start_bit_bi0 <= bits1.bit_length;
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// is this a bytes1 byte
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let is_bytes1_byte : boolean = start_bit_is_of_first_array && stop_bit_is_of_first_array;
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let is_boundary_byte : boolean = start_bit_is_of_first_array && !stop_bit_is_of_first_array;
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// need to work out the ping_pong bs up here because js is dumb and I
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// can't put lets between elseifs
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// alright, now we're in the case of only copying from the second array
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// we have two cases:
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// ping-pong:
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// ABCD_EFGH 1234_5678
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// - ---- ---
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// copying these bits
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// ping:
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// ABCD_EFGH <end>
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// - ---- 000
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//
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// how to distinguish between these two??
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//
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// we're in the ping case when the start_bit_bi0 corresponds to the
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// final byte of the second array
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//
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// ok
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//
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// we need to compute the bit address in the second array that
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// corresponds to the bit address at the beginning of this byte in the
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// result array
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let bits2_addr_bi0 : number = start_bit_bi0 - bits1.bit_length;
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// I think the variable is
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// bits_left_to_copy = bits2.bit_length - bit_addr2_bi0
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// no + 1 because the current bit is uncopied,
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// so if bit_addr2_bi0 = 7 and bits2.bit_length is 8, it means we
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// have the last bit to copy
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// cases:
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// bits_left_to_copy <= 0 ->
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// this would mean we have more bits to copy, but are out of
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// source bits. should be impossible if bits_null is correct
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// bits_left_to_copy <= 8 ->
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// this would mean we are going to fill this last byte in the
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// result array with the correct bits from array2, but how we
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// do this will depend on how those are arranged in bytes2
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// (whether we grab one or two bytes)
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//
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// this is the tricky case
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//
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// I think what matters here is the byte address in the second array
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// if we're on the last byte
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// 8 < bits_left_to_copy ->
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// this means we can safely grab two bytes from bytes2, and do
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// our bitshifting to make it correct
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//
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// FIXME
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let bits_left_to_copy : number = bits2.bit_length - bits2_addr_bi0;
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// no the variable that matters is which byte we're on in the result
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let this_bytes2_addr_i0 : number = Math.floor(bits2_addr_bi0 / 8);
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let next_bytes2_addr_i0 : number = this_bytes2_addr_i0 + 1;
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let bitshift_amt : number = bits1.bit_length % 8;
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let ping : boolean = next_bytes2_addr_i0 === bytes2.length;
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// simple case: this is a byte from the first array
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// just copy it
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if (is_bytes1_byte)
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result_bytes[i] = bytes1[i];
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// this is a boundary byte
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// further cases:
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// second bit length is 0 ->
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// ABCD_EF-- <empty>
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// ^ starting here
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// just copy first byte and move along
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else if (is_boundary_byte && (bits2.bit_length === 0))
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result_bytes[i] = bytes1[i];
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// boundary byte, and there is at least one byte in the second array
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else if (is_boundary_byte)
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{
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// copy over the first byte
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result_bytes[i] = bytes1[i];
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// take the first byte from the second array
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let first_byte_of_second_array : number = bytes2[0];
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// bytes1:
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// ABCD_EF00
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// 6
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// bytes2:
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// 1234_5678
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// 0000_0012
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// and bitshift it right by that amount
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let bitshift_amt : number = bits1.bit_length % 8;
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result_bytes[i] ^= first_byte_of_second_array >> bitshift_amt;
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}
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// last byte of second array
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else if (ping)
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result_bytes[i] = (bytes2[this_bytes2_addr_i0] << bitshift_amt);
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// ping-pong: not last byte of second array
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else
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result_bytes[i] = (bytes2[this_bytes2_addr_i0] << bitshift_amt) ^ (bytes2[next_bytes2_addr_i0] << bitshift_amt);
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}
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return {bit_length : result_bit_length,
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bytes : result_bytes};
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}
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