[wip] factoring vdk out into several packages

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2023-05-25 15:05:48 -06:00
parent 35ef2e0b1d
commit ee30eaaf7f
231 changed files with 13800 additions and 0 deletions
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/**
* Concatenate two bitstrings
*/
function
bits_concat
(bits1 : bits,
bits2 : bits)
: bits
{
let result_bit_length : number = bits1.bit_length + bits2.bit_length;
let bytes1 : Uint8Array = bits1.bytes;
let bytes2 : Uint8Array = bits2.bytes;
// using zeros here because of our xor trick in a minute
let result_bits : bits = bits_zeros(result_bit_length);
let result_bytes : Uint8Array = result_bits.bytes;
// alright so
// we can start by copying the first bytes into result bytes
for (let bytes1_idx0 = 0;
bytes1_idx0 < bytes1.length;
bytes1_idx0++)
{
result_bytes[bytes1_idx0] = bytes1[bytes1_idx0];
}
// next
// we need to calculate the left-shift offset
// this will be 8 - (bytes1.bit_length % 8)
let num_trailing_zeros_in_first_array : number = 8 - (bits1.bit_length % 8);
// so
// bytes1: ABCD_EF00
// bytes2: GH12_3000
// result: ABCD_EFGH 1230_0000
// ah ok, so we need to for each byte in the second array
// take the first however many bits, xor it with the existing byte
// then take the last however many bits and place them into the next byte
// this is super confusing but
// ABCD_EF00
// GH12_3456
// operation:
// ABCD_EF00
// xor 0000_00GH
// = ABCD_EFGH 1234_5600
//
// then on the next iteration
// 1234_5600
// abcd_efgh
// ->
// 1234_56ab cdef_gh00
//
// ah so there's a pattern
// however many trailing 0s there are in the first array
// say there's 2
// we take the first 2 bits of the upcoming byte
// xor that against the current byte
// take the last 6 bits of the upcoming byte
// set the next byte to that
//
// have to think about edge behavior
// this is ripe for off-by-1 errors
// but i think the general idea is right
//
// so we start the iteration
// on the last byte of the first array
let last_byte_of_first_array_idx0 : number = bytes1.length - 1;
// and we end
// on the second-to-last-byte of the result array
let second_to_last_byte_of_result_array_idx0 : number = result_bytes.length - 2;
// the reason we do that is because we're doing this is because we are
// going along, xoring against the current byte and then setting the next
// byte
//
// ok so
for (let this_result_byte_idx0 = last_byte_of_first_array_idx0;
this_result_byte_idx0 <= second_to_last_byte_of_result_array_idx0;
this_result_byte_idx0++)
{
let this_result_byte : number = result_bytes[this_result_byte_idx0];
// ok here we need to fish out the relevant byte of the second array
// gaaah
// so this will be 0 at the start of the loop
let relevant_byte_of_second_array_idx0 : number = this_result_byte_idx0 - last_byte_of_first_array_idx0;
let relevant_byte_of_second_array : number = bytes2[relevant_byte_of_second_array_idx0];
// ok so let's fish out the leading digits
// the number of leading digits is the number of trailing 0s in the first array
let num_leading_digits : number = num_trailing_zeros_in_first_array;
let num_trailing_digits : number = 8 - num_leading_digits;
// suppose there are 2 leading digits and 6 trailing digits
// ABCD_EFGH
// leading digits are
// ABCD_EFGH >> 6 = 0000_00AB
// trailing digits are
// (ABCD_EFGH << 2) % 255 = CDEF_GH00
let leading_digits : number = relevant_byte_of_second_array >> num_trailing_digits;
let trailing_digits : number = (relevant_byte_of_second_array << num_leading_digits) % 255;
// xor the current byte against the leading digits
let new_this_result_byte : number = this_result_byte ^ leading_digits;
result_bytes[this_result_byte_idx0] = new_this_result_byte;
// set the next byte to the trailing digits
result_bytes[this_result_byte_idx0 + 1] = trailing_digits;
}
// i think we're done
return {bit_length : result_bit_length,
bytes : result_bytes};
}